scipy.sparse.bsr_matrix.diagonal#

bsr_matrix.diagonal(k=0)[source]#

Returns the kth diagonal of the array/matrix.

Parameters:

kint, optional: Which diagonal to get, corresponding to elements a[i, i+k]. Default: 0 (the main diagonal).

New in version 1.0.

See also

numpy.diagonal: Equivalent numpy function.

Examples

>>> from scipy.sparse import csr_array
>>> A = csr_array([[1, 2, 0], [0, 0, 3], [4, 0, 5]])
>>> A.diagonal()
array([1, 0, 5])
>>> A.diagonal(k=1)
array([2, 3])